Max-Spec vs Spec
This is an article on why using Max-Spec and Spec do not matter much if the ring $A$ is a Jacobson ring. Definition. A ring $A$ is a Jacobson ring if every prime ideal of $A$ is an intersection of maximal ideals. In other words, \[ \mathrm{Nil}(A) = \bigcap_{\mathfrak{p}} \mathfrak{p} = \bigcap_{\mathfrak{m}} \mathfrak{m} = \mathrm{Jac}(A) \] Proposition. Let $X =\mathrm{Spec}(A)$ and $X_0 = \mathrm{MaxSpec}(A)$, i.e. the set of closed points of $X$. The $X_0$ is a very dense subset of $X$. We show that some topological properties are preserved. Let's first describe what it means for $\mathrm{Spec}(A)$ to be disconnected. By this means that there exist disjoint closed subsets $V(I)$ and $V(J)$ that cover $\mathrm{Spec}(A)$. In other words, 1) $V((0))=\mathrm{Spec}(A) = V(I) \cup V(J) = V(I \cap J)$. 2) $V((1)) = \varnothing = V(I) \cap V(J) = V(I + J)$. This is same as saying that 1') $\sqrt{I \cap J} = \sqrt{(0)} = \mathrm{Nil}(A...